Source code for lsst.utils.get_caller_name
#
# LSST Data Management System
#
# Copyright 2008-2017 AURA/LSST.
#
# This product includes software developed by the
# LSST Project (http://www.lsst.org/).
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# This program is free software: you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
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from __future__ import absolute_import, division, print_function
import inspect
__all__ = ["get_caller_name"]
[docs]def get_caller_name(skip=2):
"""Get the name of the caller method.
Any item that cannot be determined (or is not relevant, e.g. a free
function has no class) is silently omitted, along with an
associated separator.
Parameters
----------
skip : `int`
How many levels of stack to skip while getting caller name;
1 means "who calls me", 2 means "who calls my caller", etc.
Returns
-------
name : `str`
Name of the caller as a string in the form ``module.class.method``.
An empty string is returned if ``skip`` exceeds the stack height.
Notes
-----
Adapted from from http://stackoverflow.com/a/9812105
by adding support to get the class from ``parentframe.f_locals['cls']``
"""
stack = inspect.stack()
start = 0 + skip
if len(stack) < start + 1:
return ''
parentframe = stack[start][0]
name = []
module = inspect.getmodule(parentframe)
if module:
name.append(module.__name__)
# add class name, if any
if 'self' in parentframe.f_locals:
name.append(type(parentframe.f_locals['self']).__name__)
elif 'cls' in parentframe.f_locals:
name.append(parentframe.f_locals['cls'].__name__)
codename = parentframe.f_code.co_name
if codename != '<module>': # top level usually
name.append(codename) # function or a method
return ".".join(name)