nansigmaMad¶
- lsst.analysis.tools.nansigmaMad(x, axis=0, center=<function median>, *, scale='normal', nan_policy='omit')¶
Compute the median absolute deviation of the data along the given axis.
The median absolute deviation (MAD, [1]) computes the median over the absolute deviations from the median. It is a measure of dispersion similar to the standard deviation but more robust to outliers [2].
The MAD of an empty array is
np.nan
.New in version 1.5.0.
- Parameters:
- xarray_like
Input array or object that can be converted to an array.
- axisint or None, optional
Axis along which the range is computed. Default is 0. If None, compute the MAD over the entire array.
- centercallable, optional
A function that will return the central value. The default is to use np.median. Any user defined function used will need to have the function signature
func(arr, axis)
.- scalescalar or str, optional
The numerical value of scale will be divided out of the final result. The default is 1.0. The string “normal” is also accepted, and results in
scale
being the inverse of the standard normal quantile function at 0.75, which is approximately 0.67449. Array-like scale is also allowed, as long as it broadcasts correctly to the output such thatout / scale
is a valid operation. The output dimensions depend on the input array,x
, and theaxis
argument.- nan_policy{‘propagate’, ‘raise’, ‘omit’}, optional
Defines how to handle when input contains nan. The following options are available (default is ‘propagate’):
‘propagate’: returns nan
‘raise’: throws an error
‘omit’: performs the calculations ignoring nan values
- Returns:
- madscalar or ndarray
If
axis=None
, a scalar is returned. If the input contains integers or floats of smaller precision thannp.float64
, then the output data-type isnp.float64
. Otherwise, the output data-type is the same as that of the input.
See also
Notes
The
center
argument only affects the calculation of the central value around which the MAD is calculated. That is, passing incenter=np.mean
will calculate the MAD around the mean - it will not calculate the mean absolute deviation.The input array may contain
inf
, but ifcenter
returnsinf
, the corresponding MAD for that data will benan
.References
[1]“Median absolute deviation”, https://en.wikipedia.org/wiki/Median_absolute_deviation
[2]“Robust measures of scale”, https://en.wikipedia.org/wiki/Robust_measures_of_scale
Examples
When comparing the behavior of
median_abs_deviation
withnp.std
, the latter is affected when we change a single value of an array to have an outlier value while the MAD hardly changes:>>> import numpy as np >>> from scipy import stats >>> x = stats.norm.rvs(size=100, scale=1, random_state=123456) >>> x.std() 0.9973906394005013 >>> stats.median_abs_deviation(x) 0.82832610097857 >>> x[0] = 345.6 >>> x.std() 34.42304872314415 >>> stats.median_abs_deviation(x) 0.8323442311590675
Axis handling example:
>>> x = np.array([[10, 7, 4], [3, 2, 1]]) >>> x array([[10, 7, 4], [ 3, 2, 1]]) >>> stats.median_abs_deviation(x) array([3.5, 2.5, 1.5]) >>> stats.median_abs_deviation(x, axis=None) 2.0
Scale normal example:
>>> x = stats.norm.rvs(size=1000000, scale=2, random_state=123456) >>> stats.median_abs_deviation(x) 1.3487398527041636 >>> stats.median_abs_deviation(x, scale='normal') 1.9996446978061115